2 Answers

Piyush Kansal · Answer 1 · 2021-02-17T14:06:19+0000

Answer:

(See explanation)

Step-by-step explanation:

The spring with larger spring constant is those which exhibits a larger natural frequency.

$\omega = \sqrt{(k)/(m) }$

Ani Menon · Answer 2 · 2021-02-22T10:57:00+0000

Answer: The spring that is oscilating faster (has bigger frequency)

Step-by-step explanation:

We know that the frequency of oscilation of a spring is:

w = √(k/m)

Where k is the spring constant and m is the mass of the blocks, then if both blocks are identical, also their mases.

This means that if we see that one of the springs oscilates faster ( the frequency is larger) this should mean that the spring constant is larger.

Please log in or register to add a comment.