Question

In a rhombus ABCD, m∠A = 31°. Point O is a point of intersection of diagonals. Find the measures of the angles of triangle ΔBOC.

m
SHOW PROPER WORK

Answer 1

Since angle A = 31°, C = 31°
Sum of all angles = 360°
So 2x + 62 = 360
x = 149°
Diagonals are perpendicular to each other, so triangle BOC has 90° + 31°:2 + 149°:2 = 90° + 15.5° + 74.5° = 180°

B = 74.5°
O = 90°
C = 15.5°