Question

A) s o of socl2 (b) t at which the reaction becomes nonspontaneous so3(g) + scl2(l) → socl2(l) + so2(g) δg o rxn = −75.2 kj so3(g) scl2(l) socl2(l) so2(g) δh o f (kj/mol) −396 −50.0 −245.6 −296.8 s o (j/mol · k) 256.7 184 − 248.1

Answer 1

ΔS° = 121kJ , T = 1335K

Step-by-step explanation:

The reaction:

SO₃(g) + SCl₂=> SOCl₂(l) + SO₂(g)

parameters

SO₃(g) SCl₂(l) SOCl₂(l) SO₂(g)

ΔH°f(kJ/mol) -396 -50.0 -245.6 -296.8

S°(J/mol.k) 256.7 184 - 248.1

ΔG°r = -75.2 kJ

a).

S° of SOCl₂

ΔH°rxn = ΔH°f[Product] - ΔH°f[reactant]

ΔH°rxn = [1 mole * ΔH°f(SOCl2(l)) + 1 mol * ΔH°f(SO2(g))] - [1 mol *ΔH°f(SO3(g)) + 1 mole ΔH°f(SCl2(l))]

ΔH°rxn = [1 mole * -245.6kJ/mol + 1 mol * -296.8kJ/mol] - [1 mol * -396kJ/mol + 1 mole * -50kJ/mol]

ΔH°rxn = -96.4 kJ

Check the added file for other comprehensive solution