Answer:
p = 0.293
Conclusion:
"There is insufficient evidence to state that the distribution of fish in Green Valley Lake is not the same as the distribution of fish in Echo Lake."
Explanation:
------------R/trout--O/trout---bass--catfish---total
GVL - - - 105 - - - 27 - - - - - 35--- 24 - - - 191
EL - - - - 135------- 48-------- 67 - - 43 - - - 293
Total - - 240 - - - 75 - - - - - 102--- 67 - - - 484
Note : GVL = GREEN VALLEY LAKE ; EL = ECHO LAKE.
H0: The distribution of fish caught in green valley is the same as that caught in Echo lake.
H1: The distribution of fish caught in Green Valley lake is different from that caught in Echo valley lake.
Using the chi-squared test statistic calculator ;
χ2 = 3.7269
p-value = 0.2925.
p-value = 0.293
Conclusion:
"There is insufficient evidence to state that the distribution of fish in Green Valley Lake is not the same as the distribution of fish in Echo Lake."