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What is the product? StartFraction 2 y Over y minus 3 EndFraction divided by StartFraction 4 y minus 12 Over 2 y + 6 EndFraction

User Albie
by
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2 Answers

3 votes

Answer:

d

Explanation:

User David Alsh
by
8.5k points
3 votes

Answer:


(y^2+3y)/(y^2-6y+9)

Explanation:

When we write this using appropriate math symbols, it is easier to see the solution. To evaluate this, we multiply by the inverse of the denominator fraction.


(2y)/(y - 3)/ ( 4 y - 12)/(2 y + 6)=(2y)/(y-3)\cdot(2y+6)/(4y-12)\\\\=(4y(y+3))/(4(y-3)^2)}=\boxed{(y^2+3y)/(y^2-6y+9)}

User Ariful
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