Answer:
a) Null hypothesis H₀: μ₁ = μ₂
Alternative hypothesis Hₐ: μ₁ ≠ μ₂
b) Critical
is ±1.985523
c) The test statistic t is -0.1276
d) P-value > α = 0.05, we accept the null hypothesis
e) There is sufficient statistical evidence to suggest that the average weight of boys and girls are exactly the same
Explanation:
a) Null hypothesis H₀: μ₁ = μ₂, the average weight of boys and girls are the same
Alternative hypothesis Hₐ: μ₁ ≠ μ₂ the average weight of boys and girls are not the same
b) Sample size, boys, n₁ = 60, girls, n₂ = 50
Mean height, boys,
= 123.5 cm, girls,
= 126.2 cm
Population variance, boys s₁ = 98, girls, s₂ = 120
The critical value at 95% confidence, degrees of freedom (smaller between n₁ and n₂) df = 50 - 1 = 49, α = (1 - 0.95)/2 = 0.025 the critical t is given from t relations as follows;
Critical
= ±1.985523
c) For the test statistic, we have;
Plugging in the values where μ₁ = μ₂, we have;
The test statistic t = -0.1276
From t relations, we have the p-value , p = 0.8987748
d) Therefore, since the p-value > α = 0.05, we accept the null hypothesis
e) Based on the analysis, there is sufficient statistical evidence to suggest that the average weight of boys and girls are exactly the same.