Question

A stock solution of HNO3HNO3 is prepared and found to contain 12.7 M of HNO3HNO3. If 25.0 mL of the stock solution is diluted to a final volume of 0.500 L, the concentration of the diluted solution is ________ M.

Answer 1

Answer: The concentration of the diluted solution is 0.635 M.

Step-by-step explanation:

The given data is as follows.

`M_(1)` = 12.7 M,
`V_(1)` = 25.0 ml = 0.025 L (as 1 ml = 0.001 L)

`M_(2)` = ? ,
`V_(2)` = 0.5 L

Therefore, we will calculate the molarity of the solution as follows.

`M_(1)V_(1) = M_(2)V_(2)`

`12.7 M * 0.025 L = M_(2) * 0.5 L`

`M_(2)` = 0.635 M

Thus, we can conclude that the concentration of the diluted solution is 0.635 M.