Answer:
Check the explanation
Explanation:
0.0162 will be the likelihood of having 5 defective televisions at least in a shipment of 100 given that 0.02 is the true proportion of defective televisions.
Since the P-value 0.0162 is smaller than 0.05, it will be considered significant at that level, so we should reject the null hypothesis in favor of the alternative hypothesis.