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Use the quadratic f(x)=x²+3x-4 and use any method to solve for the Zeros. Use the same function to solve for x when y is 6. F(x)=6 Last, solve f(x)=10 for x.

1 Answer

4 votes

Answer:

a)
f(x) = (x+4)\cdot (x-3), b)
x = -5 or
x = 2, c)
x \approx 2.531 or
x \approx -5.531

Explanation:

a) The function is solved by factorization:


f(x) = (x+4)\cdot (x-3)

b) The function has the following form:


x^(2) + 3\cdot x - 4 = 6


x^(2) + 3\cdot x - 10 = 0

The roots of the polynomial are found by factorization:


(x+5)\cdot (x-2) = 0


x = -5 or
x = 2

c) The function has the following form:


x^(2) + 3\cdot x - 4 = 10


x^(2) + 3\cdot x - 14 = 0

The roots of the polynomial are determined by the General Formula for the Second-Order Polynomial:


x_(1) = \frac{-3+\sqrt{3^(2)-4\cdot (1)\cdot (-14)}}{2\cdot (1)}


x_(1) \approx 2.531


x_(2) = \frac{-3-\sqrt{3^(2)-4\cdot (1)\cdot (-14)}}{2\cdot (1)}


x_(2) \approx -5.531

User KevinAlbs
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