Question

Read the question carefully

2 points

1. A basketball court is in the shape of a rectangle

that is 94 feet long and 50 feet wide. What is

the length of a diagonal of the court? Round to

the nearest tenth.

Answer 1

106.5 feet

Explanation:

We are given that

Length of rectangle=l=94 feet

Breadth of rectangle,b=50 feet

We have to find the length of diagonal of the court.

Pythagoras theorem:

`(Hypotenuse)^2=(perpendicular\;side)^2+(base)^2`

Using the theorem

`(Diagonal)^2=(94)^2+(50)^2`

`(Diagonal)^2=8836+2500`

`(Diagonal)^2=11336`

`Diagonal=√(11336)`

Length of diagonal of court=106.5 feet