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Shaun's tent (shown below) is a triangular prism. Find the surface area, including the floor, of his tent. \text{ m}^2 m 2 start text, space, m, end text, squared

User Tamuren
by
4.2k points

2 Answers

5 votes

Answer:2400

Explanation:

User Kheengz
by
5.0k points
4 votes

Answer:

52.8 square m

Explanation:

We are given that

Length of rectangular face of Shaun's tent=5 m

Breadth of rectangular face of Shaun's tent=3 m

Base of triangular face=1.5+1.5= 3m

Height of triangular face=2.6 m

Area of rectangle=
length* breadth

Using the formula

Area of 3 rectangular face=
3* 5* 3=45m^2

Area of two triangular face =
2* (1)/(2)* base* height

Area of two triangular face=
3* 2.6=7.8 m^2

Area of tent=Area of 3 triangular faces+area of two triangular faces

Area of tent=
45+7.8=52.8m^2

Shaun's tent (shown below) is a triangular prism. Find the surface area, including-example-1
User Tyrel
by
4.7k points