Question

Two negative charges that are both - 3.8 C push each other apart with a force of 19.0 N. How far apart are the two charges?

Answer 1

The separation distance between the two charges must be 82704.2925 m

Step-by-step explanation:

Given:

Two negative charges that are both q = -3.8 C

Force of 19 N

Question: How far apart are the two charges, s = ?

First, you need to get the electrostatic force of this two negative charges:

`F=(kq)/(s^(2) ) \\s=\sqrt{(kq)/(F) }`

Here

k = electric constant of the medium = 9x10⁹N m²/C²

Substituting values:

`s=\sqrt{(9x10^(9)*(-3.8)^(2) )/(19) } =82704.2925m`