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A piston is compressed from a volume of 8.47 L to 2.62 L against a constant pressure of 1.93 atm. In the process, there is a heat gain by the system of 360. J. 371.2 Incorrect: Your answer is incorrect. J

User Thanatos
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2 Answers

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Final answer:

The question relates to thermodynamics in physics, focusing on gas expansion or compression in a piston and its related work, heat transfer, and temperature change.

Step-by-step explanation:

The question involves the concept of thermodynamics, which is a branch of physics dealing with heat, work, and energy transfer. When gas in a piston expands or compresses, it can perform work on its surroundings, and there may also be a transfer of heat between the system and its surroundings. The specifics of the temperature change, work done, and energy transfer depend on factors such as initial and final volume, pressure, and the heat capacity of the system or the environment it's in contact with.

User Duy Bui
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5 votes
5 votes

Answer:

1144J

Step-by-step explanation:

To find the heat gain by the system you consider that all heat is generated by the work done by the piston, that is:


Q=W=P\Delta V

P: constant pressure = 1.93atm= 1.93(101325pas) = 195557.25J/m^3

ΔV: change in the volume 8.47-2.62L=5.85L

5.85(1000cm^3)=5.85(1000(10^-2m)^3)=5.85*10^{-3}m^3

By replacing the values of V and P you obtain:


1Q=(195557.25J/m^3)(5.85*10^(-3)m^3)=1144J

hence, the gain by the system is 1144J

User Cyrene
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