Question

Find fq, the vertical force that pier q exerts on the right end of the bridge. express the vertical force at q in terms of m and g

Answer 1

`F_Q=(Mg)/(3)`

Step-by-step explanation:

We are given that

Length of beam=L

Mass of object=M

We have to find the FQ , the vertical force that pier exerts on the right end of the bridge .

Torque about P

`F_Q(3L)-MgL=0`

`F_Q(3L)=MgL`

`F_Q=(MgL)/(3L)`

`F_Q=(Mg)/(3)`

Hence, the force that exerted pier Q exerts on the right end of the bridge is given by

`F_Q=(Mg)/(3)`