Answer:
Check the explanation
Explanation:
Let x be the length of the north and south walls, y the length of the east and
west walls, and z the height of the building. The heat loss is given by
h = 10(2yz) + 8(2xz) + 1(xy) + 5(xy) = 6xy + 16xz + 20yz.
The volume is 4000 m3, so xyz = 4000, and we substitute z = 4000/(xy) to obtain the
heat loss function
h(x, y) = 6xy + 80, 000/x+ 64, 000/y.
a) Since 4000/(xy)≥4, xy≤1000, i.e., y ≤1000/x. Also x ≥ 30 and y≥ 30, so the
domain of h is D= {(x, y) : x ≥30, 30≤ y≤ 1000/x}.
is the region bounded from below by the horizontal line segment from (30
,30)to ( 100/3 , 30) (let us call this line ), from the right by the portion of the hyperbola y = 1000/x from (30, 100/3 ) to ( 100/3) (we call this curve ) and from the left by the vertical line segment from (30, 30) to (30, 100/3 ) (denote this by )
b) Kindly check the solution to question B in the attached image below.
h is h(30, 30) = 10, 200 and the dimensions of the
building that minimize heat loss are walls 30 m in length and height 4000
/302 =
40
/9 = 4.44 m.
(c) From part (b), the only critical point of
h, which gives a local and absolute minimum x ≈ 25.54 m, y = 20.43 m, z ≈ 4000 /(25.54)(20.43) ≈ 7.6
I hope it helped you.
is approximately
h(25.54, 20.43) ≈ 9396. So a building of volume 4000 m3 with dimensions.