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2 votes
Solve for x:
1 1/5x−2 1/3<1/7x+1 1/2

User Klaycon
by
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1 Answer

3 votes

Answer:
x<3(175)/(222)

Explanation:


1(1)/(5)x-2(1)/(3)<(1)/(7)x+1(1)/(2)

Add
2(1)/(3) on both sides and subtract
(1)/(7)x on both sides to leave x's on the left side and independent values on the right.


(2(1)/(3)-(1)/(7)x) +1(1)/(5)x-2(1)/(3)<(1)/(7)x+1(1)/(2)+(2(1)/(3)-(1)/(7)x)


1(1)/(5)x-(1)/(7)x<1(1)/(2)+2(1)/(3)

Solve the fractions.


1((1)/(5)-(1)/(7))x<1+2((1)/(2)+(1)/(3))


1(((1)(7)-(5)(1))/((5)(7)) )x<3(((1)(3)+(2)(1))/((2)(3)) )


1((7-5)/(35) )x<3((3+2)/(6) )


1((2)/(35) )x<3((5)/(6))


1(2)/(35)x<3(5)/(6)

Convert the mixed fraction
1(2)/(35) to an improper fraction. You can do this by multiplying 1 times 35 and adding 2.


(37)/(35)x<3(5)/(6)

Now use the reciprocal (inverse fraction) and multiply on both sides to isolate x.


((35)/(37)) ((37)/(35))x <(3(5)/(6))((35)/(37))


x<3((5)/(6)*(35)/(37))


x<3((175)/(222) )


x<3(175)/(222)

User Paul Bone
by
4.7k points