Question

For the same mixture, under the same conditions described in problem 7, calculate keq for 2nh3 (g) n2 (g) + 3h2(g). how is the keq for a forward reaction related to the keq for a reverse reaction

Answer 1

Answer: The relation between the forward and reverse reaction is
`K_f=(1)/(K_r)`

Step-by-step explanation:

For the given chemical equation:

`2NH_3(g)\rightleftharpoons N_2 (g)+3H_2(g)`

The expression of equilibrium constant for above equation follows:

`K_f=([N_2][H_2]^3)/([NH_3]^2)` .......(1)

The reverse equation follows:

`N_2 (g)+3H_2(g)\rightleftharpoons 2NH_3(g)`

The expression of equilibrium constant for above equation follows:

`K_r=([NH_3]^2)/([N_2][H_2]^3)` .......(2)

Relation expression 1 and expression 2, we get:

`K_f=(1)/(K_r)`

Hence, the relation between the forward and reverse reaction is
`K_f=(1)/(K_r)`