Question

The circumference of the inner circle is 22 ft. The distance between the inner circle and the outer circle is 3 ft. By how many feet is the circumference of the outer circle greater than the circumference of the inner​ circle?

Answer 1

18.8 ft approximately

Explanation:

The formula for the circumference of a circle is C = 2*pi*r, where pi is approximately 3.14 and r is the radius of the circle.

The circumference of the inner circle is 22 ft. Thus, C = 22 ft = 2(3.14)(r). Solving this for r, we get:

22 ft

r = --------------- = 3.503 ft

6.28

Since 3 ft separate the inner and outer circles, the radius of the outer circle is (3.5 ft+ 3 ft), or 6.5 ft, and so the circumference of the outer circle is

C = 2(3.14)(6.5 ft), or approximately 40.8 ft.

Thus, the circumference of the outer circle exceeds that of the inner circle by (40.8 ft - 22 ft), or 18.8 ft approximately.

The difference in the two circumferences is (157 ft - 22 ft), or 135 ft