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A mountain bike tires completes 20 revolution and travels 136ft. Rounded to the nearest inch , what is the diameter of the bike tires ? Use 3.14 for (pi) .Enter your answer in the box

User Ddimitrov
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1 Answer

3 votes

Answer:

26.04 inches

Explanation:

A revolution is in the shape of a circle.

We can therefore say that the bike tires that complete 20 revolutions complete the length of 20 circumferences of the tires.

The length of the 20 revolutions (20 circumferences) is 136 ft

Therefore, the length of one revolution and hence, one circumference is:

C = 136 / 20 = 6.8 ft

The circumference of a circle is given as:

C = pi * d

Where d = diameter of the circle.

Hence, the diameter of the tire will be:

6.8 = 3.14 * d

d = 6.8 / 3.14

d = 2.17 ft

1 foot is equal to 12 inches, hence, 2.17 ft in inches will be:

2.17 * 12 = 26.04 inches

The diameter of the tire is 26.04 inches.

User Rkhb
by
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