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A sprinkler head is equidistant from flower garden A and a small shrub B. The sprinkler waters in a

circular pattern. If the length of minor arc AB is 12 feet and the radius of the circle is 10 feet, find the

measure of the central angle subtended by minor arc AB, to the nearest degree.

1 Answer

4 votes

Answer:


69^(\circ)

Explanation:

We are given that

Length of minor arc AB=12 feet

Radius of circle=r=10 feet

Let x be the measure of central angle subtended by minor arc AB.

We know that

Length of an arc=
(Central\;angle)/(360)* 2\pi r

Where
\pi=3.14

Using the formula


12=(x)/(360)* 2* 3.14* 10


x=(12* 360)/(2* 3.14* 10)


x=69^(\circ)

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