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What is the radius of a circle with center (2,1) and containing point (0,1)

User Aiyagaze
by
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1 Answer

3 votes

Answer:

The radius is 2 or The simplified radius is 4 ( if needed).

Explanation:

- The equation of a circle is:


(x-h)^2+(y-k)^2=r^2 where the center is
(h,k), the point as
(x,y) and the radius
r^2.

-Put both the center and the point onto that equation:


(0-2)^2+(1-1)^2=r^2

-Then, solve them up:


(0-2)^2+(1-1)^2 =r^2


(-2)^2+0=r^2


4 + 0=r^2


4 = r^2


√(4) =√(r^2)


2=r

User Vidyanand
by
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