Question

A sample of gas is held at 100oc at a volume of 20 L.if the volume is increased to 40 L what is the new temperature of the gas in celcius.

Answer 1

The new temperature of the gas is 200 Celsius degrees.

Step-by-step explanation:

Charles's Law consists of the relationship between the volume and temperature of a certain amount of ideal gas, which is maintained at a constant pressure, by means of a proportionality constant that is applied directly.

In this way, Charles's law is a law that says that the quotient that exists between volume and temperature will always have the same value:

`(V)/(T) =k`

Assuming you have a certain volume of gas V1 that is at a temperature T1 at the beginning of the experiment, if you vary the volume of gas to a new value V2, then the temperature will change to T2, and it will hold:

`(V1)/(T1) =(V2)/(T2)`

In this case:

• V1= 20 L
• T1= 100 °C
• V2= 40 L
• T2= ?

Replacing:

`(20)/(100) =(40)/(T2)`

Solving:

`T2=(40)/((20)/(100) )`

T2=200 °C

The new temperature of the gas is 200 Celsius degrees.

Answer 2

473°C

Step-by-step explanation:

We'll begin by analysing what was given from the question. This is illustrated below:

Initial temperature (T1) = 100°C

Initial volume (V1) = 20 L

Final volume (V2) = 40 L

Final temperature (T2) =?

Next, we shall be converting the temperature in celsius to Kelvin temperature. This is illustrated below:

Temperature (Kelvin) = temperature (celsius) + 273

Initial temperature (T1) = 100°C = 100°C + 273 = 373K

Next, we shall obtain the new temperature by applying the Charles' law equation. This is illustrated below:

V1/T1 = V2/T2

20/373 = 40/T2

Cross multiply to express in linear form

20 x T2 = 373 x 40

Divide both side by 20

T2 = (373 x 40) /20

T2 = 746K

Next, we shall be converting the new temperature obtained from Kelvin to celsius temperature. This is illustrated below:

Temperature (celsius) = Temperature (Kelvin) - 273

Temperature (celsius) = 746K - 273

Temperature (celsius) = 473°C