Question

Solve for x ~

`x {}^(2) - 16x = 0`


thankyou ~​

Answer 1

Explanation:

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Answer 2

`\qquad\qquad\huge\underline{{\sf Answer}}`

Here we go ~

`\qquad \tt \dashrightarrow \: {x}^(2) - 16x = 0`

`\qquad \tt \dashrightarrow \: x(x - 16) = 0`

Now, there are two possibilities ~

`\qquad \tt \dashrightarrow \:x = 0`

or

`\qquad \tt \dashrightarrow \:x - 16 = 0`

`\qquad \tt \dashrightarrow \:x = 16`