Question

The primary coil of a transformer has N1 = 275 turns, and its secondary coil has N2 = 2,200 turns. If the input voltage across the primary coil is Δv = (160 V)sin ωt, what rms voltage is developed across the secondary coil?

Answer 1

Secondary voltage of transformer is 905.23 volt

Step-by-step explanation:

It is given number of turns in primary of transformer
`N_1=275`

Number of turns in secondary
`N_2=2200`

Input voltage equation of the transformer

`\Delta v=160sin\omega t`

Here
`v_(max)=160volt`

`v_(rms)=(160)/(√(2))=113.15volt`

For transformer we know that

`(V_1)/(V_2)=(N_1)/(N_2)`

`(113.15)/(V_2)=(275)/(2200)`

`V_2=905.23Volt`

Therefore secondary voltage of transformer is 905.23 volt