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What is the missing constant term in the perfect square that starts with x^2-12xx 2 −12xx

User Wilkins
by
6.6k points

2 Answers

4 votes

Answer:

36

Explanation:

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User Robotronx
by
6.2k points
5 votes

We have been given an expression
x^2-12x. We are asked to determine the missing term in the expression that will make the expression a perfect square.

To complete a square, we need to add the square of half of the coefficient of x.

We can see that coefficient of x is
-12. To complete the square we need to find half of the square of
-12.


((-12)/(2))^2=(-6)^2=36

Upon adding 36 to our expression, we will get:


x^2-12x+36

We can see that our expression is now perfect square as we can rewrite is as:


(x-6)^2

Therefore, the missing constant term in the given perfect square would be 36.

User Roy Smith
by
6.7k points
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