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For each of the following vector fields F , decide whether it is conservative or not by computing the appropriate first order partial derivatives. Type in a potential function f (that is, \\abla f = \mathbf{F} ). If it is not conservative, type N.

A. \mathbf{F} \left( x, y \right) = \left( -10 x + 7 y \right) \mathbf{i} + \left( 7 x + 6 y \right) \mathbf{j}
f \left( x, y \right) =

B. \mathbf{F} \left( x, y \right) = -5 y \mathbf{i} - 4 x \mathbf{j}
f \left( x, y \right) =

C. \mathbf{F} \left( x, y, z \right) = -5 x \mathbf{i} - 4 y \mathbf{j} + \mathbf{k}
f \left( x, y, z \right) =

D. \mathbf{F} \left( x, y \right) = \left( -5 \sin y \right) \mathbf{i} + \left( 14 y - 5 x \cos y \right) \mathbf{j}
f \left( x, y \right) =

E. \mathbf{F} \left( x, y, z \right) = -5 x^{2} \mathbf{i} + 7 y^{2} \mathbf{j} + 3 z^{2} \mathbf{k}
f \left( x, y, z \right) =

Note: Your answers should be either expressions of x, y and z (e.g. "3xy + 2yz"), or the letter "N"

User JefferMC
by
7.5k points

1 Answer

1 vote

Answer:

(a)

Conservative

(b)

Not conservative

(c)

Conservative.

Explanation:

(a)


\mathbf{F}(x,y) = (-10x+7y,7x+6y)

Notice that


\frac{\partial\mathbf{F}_y}{\partial x} = 7

and


\frac{\partial\mathbf{F}_x}{\partial y} = 7

Therefore the field is conservative.

(b)

Notice that


\mathbf{F}(x,y) = (-5y,-4x)

and


\frac{\partial\mathbf{F}_y}{\partial x} = -4

but


\frac{\partial\mathbf{F}_x}{\partial y} = -5

Therefore is not conservative.

(c)

Notice that

To prove that the vector field is conservative you have to compute the curl of the vector field and you would get that.


\mathbf{F}(x,y,z) = (-5x,-4y,1)


\\abla * \mathbf{F} = (0,0,0)

Therefore your vector field is conservative.

User TheScholar
by
7.6k points