Question

g Use technology to find the​ P-value for the hypothesis test described below. The claim is that for a smartphone​ carrier's data speeds at​ airports, the mean is mu μ equals = 17.00 17.00 Mbps. The sample size is n equals = 22 22 and the test statistic is t equals = negative 1.576 −1.576.

Answer 1

The sample size is n = 22. So then we can find the degrees of freedom given by:

`df = n-1= 22-1 =21`

And since is a bilateral test we can find the p value with this:

`p_v = 2* P(t_(21)< -1.576) = 0.130`

And the excel code to find it is : "=2*T.DIST(-1.576,21,TRUE)"

Explanation:

For this case we have the following system of hypothesis:

Null hypothesis:
`\mu = 17`

Alternative hypothesis:
`\mu \\eq 17`

So we are conducting a bilateral test. We know that after find the statistic for this case we got
`t= \pm 1.576`

The sample size is n = 22. So then we can find the degrees of freedom given by:

`df = n-1= 22-1 =21`

And since is a bilateral test we can find the p value with this:

`p_v = 2* P(t_(21)< -1.576) = 0.130`

And the excel code to find it is : "=2*T.DIST(-1.576,21,TRUE)"