148k views
1 vote
The force of repulsion, F Newton (N).,between particles is invesrly propotional to the square of the distance dm1find the particles with the force of repulsion 20N.Find find force when distance is halved

User Zlon
by
5.7k points

1 Answer

3 votes

Answer:


F_(2) = 80\,N

Explanation:

Given the consideration of the inverse proportionality between force and distance, the following relationship is constructed and described below:


F_(1)\cdot r_(1)^(2) = F_(2)\cdot r_(2)^(2)

The force when the distance is halved is:


F_(2) = F_(1)\cdot \left((r)/(0.5\cdot r) \right)^(2)


F_(2) = 4\cdot F_(1)


F_(2) = 4\cdot (20\,N)


F_(2) = 80\,N

User Dong Nguyen
by
5.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.