Answer:
A)distance of office building from the tower = 2475.9 ft
B)Height of building: 768.77 ft
Explanation:
Suppose, we construct a trapezium, ABCD for this question.
Where;
AB is a vertical line representing T1 and is 1670 ft high
DC is a vertical line representing the office building a perpendicular distance of AD away from the foot of T1
Now, we are told that the angle of elevation from the base of an office building to the top of the tower is 34°. Thus connecting CB and BD, we have angle ADB = 34°
Now, if we draw a horizontal line from C to intersect AB at E, the angle ECB is 23°
a) from the attached image, using trigonometric ratios, we have; AB/AD = tan 34°
Thus; 1670/AD = 0.6745
AD = 1670/0.6745
AD = 2475.9 ft
b) Also, from the diagram
EB/EC = Tan 23° = 0.4245
therefore; EB = 2475.9 x 0.364
EB = 901.23 ft
Now, AE = DC = height of bldg = AB - EB = 1670 - 901.23 = 768.77 ft