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The water in an 8-m-diameter, 3-m-high above-ground swimming pool is to be emptied by unplugging a 3-cm-diameter, 25-m-long horizontal pipe attached to the bottom of the pool. Determine the maximum discharge rate of water through the pipe in liters per second.

User JJ Beck
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1 Answer

4 votes

Answer:

The maximum discharge rate of water is 4.6 L/s

Step-by-step explanation:

Given data:

d=diameter=8 m

h=height=3 m

The mathematical expression for the theoritical velocity is:


v_(th) =√(2gh) =√(2*9.8*3) =7.6681m/s

The maximum discharge can be calculate by:


Q=C_(d) Av_(th)

Here

Cd=coefficient of discharge=0.855


Q=0.855*(\pi )/(4) *d^(2) *vx_(th) =0.855*(\pi )/(4) *0.03^(2) *7.6681=0.0046m^(3) /s=4.6L/s

User Raviabhiram
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