Answer:
![\tan(X)=(77)/(36)](https://img.qammunity.org/2023/formulas/mathematics/college/1nol1unm1ue2fy94ktjnhgqd1dg0nd1426.png)
Explanation:
First we need to find the length of side WX.
To do this, use Pythagoras' Theorem:
![a^2+b^2=c^2](https://img.qammunity.org/2023/formulas/mathematics/high-school/fdnnfwrccw5g60jmi691r5gcz9ekxf8waa.png)
(where a and b are the legs, and c is the hypotenuse, of a right triangle)
![\implies WX^2+77^2=85^2](https://img.qammunity.org/2023/formulas/mathematics/college/m8km3792qmyai3aqdzfxxfhmgm7v6hk3va.png)
![\implies WX^2=85^2-77^2](https://img.qammunity.org/2023/formulas/mathematics/college/z7dy5bpvvursbjnnh8fclxr0jfdl4zoytx.png)
![\implies WX=√(85^2-77^2)](https://img.qammunity.org/2023/formulas/mathematics/college/78xrsr62sv785v2hhpumcua9gei21bd4iz.png)
![\implies WX=36](https://img.qammunity.org/2023/formulas/mathematics/college/vt02fl2247uvfwilsx95wp3e47ebh5kyfz.png)
Now use the Tan trig ratio:
![\tan(x)=\sf (O)/(A)](https://img.qammunity.org/2023/formulas/mathematics/college/iuc1s31dbwht6s95l6pwn8wtxwftyj7sxq.png)
where:
is the angle- O is the side opposite the angle
- A is the side adjacent the angle
From inspection of the triangle,
= ∠X- O = 77
- A = WX = 36
Substituting these values into the tan trig formula:
![\implies \tan(X)=(77)/(36)](https://img.qammunity.org/2023/formulas/mathematics/college/bfp6aymrbp1myo2z7233w44szbt79ljvc9.png)
Therefore, the tangent of ∠X is
![(77)/(36)](https://img.qammunity.org/2023/formulas/mathematics/college/gtzp6vk97h1ci6yjrf13dzw3um2040gohs.png)