Question

I need help with this ASAP plzzzzz

Answer 1

23.
`(4√(3) )/(3)`

24.
`(7√(3))/(3)`

25.
`6√(3)`

26.
`(10√(3) )/(3)`

27.
`14`

28.
`4√(3)`

Explanation:

To solve these i used SOHCAHTOA

`sin=(opposite)/(adjacent)\\ cos=(adjacent)/(hypotenuse) \\tan=(opposite)/(adjacent)`

23.

Find the missing side using Tangent

`tan(30)=(x)/(4)`

`4*tan(30)=x`

`(4√(3) )/(3)`

24.

Find the missing side using Tangent

`tan(30)=(x)/(7)`

`7*tan(30)=x`

`(7√(3))/(3)`

25.

Find the missing side using Tangent

`tan(30)=(x)/(18)`

`18*tan(30)=x`

`6√(3)`

26.

Find the missing side using Tangent

`tan(30)=(x)/(10)`

`10*tan(30)=x`

`(10√(3) )/(3)`

27.

Find the missing side using Tangent

`tan(30)=(x)/(14√(3) )`

`(14√(3)) *tan(30)=x`

`14`

28.

Find the missing side using Tangent

`tan(30)=(x)/(12)`

`12*tan(30)=x`

`4√(3)`