eq :- 4x - 3y - 2 =0
and coordinates :- (44/25,42/25)
Step-by-step explanation:-
The given line is 3x + 4y - 12 = 0
=> 4y = -3x + 12 ....(i)
=> y = -3x/4 + 3,
therefore, the slope of the line (i) = -3/4.
From P(-1,-2), draw PN perpendicular to the given line. (see attachment)
As we know,, m2 = -1/m1
So, the slope of the line PN = 4/3
the equation of the line through P(-1,-2) and having a slope 4/3 is :-
= > y - (-2) = 4/3 * (x - (-1))
= > 3y + 6 = 4x + 4
= > 4x - 3y - 2 = 0....(ii)
which is the required equation of the perpendicular from P to the given line. To find the coordinates of N (the foot of perpendicular), solve (i) and (ii) simultaneously. Multiplying (i) by 3 and
(ii) by 4, and on adding, we get
= > 25x - 44 = 0
= > x = 44/25
Multiplying (i) by 4 and (ii) by 3, and on subtracting, we get :-
= > 25y - 42 = 0
= > y = 42/25
Hence, the coordinates of the foot of the perpendicular are (44/25 , 42/25)
Hope it helps you!!