30.6k views
1 vote
Draw two rectangles.The first has length 6 and width 9. The second has length 3x and width 9. Write at least three different expressions for the sum of the areas of the rectangles.

User Nakkia
by
4.9k points

1 Answer

1 vote

Answer:


A = 54 +27x (1)

And using factorization (common factor) we can do this:


A = 6*9 +9*3x = 9(6+3x) (2)


A = 6*3*3 +9*3x = 3(18+9x) (3)

Explanation:

In the figure attached we see the two triangles required one with a length of 6 and a width of 9 and the other with a length of 3x and width of 9.

For the first rectangle we know that the area can be founded with this formula:


A_1 = bh = 6*9=54

And for the second rectangle the area can be founded similar like this:


A_2 = 9*3x = 27x

And since we are interested in the sum of the two areas we have this:


A = A_1 +A_2

We need a 3 different expression for the sum of the areas so we can do this:


A = 54 +27x (1)

And using factorization (common factor) we can do this:


A = 6*9 +9*3x = 9(6+3x) (2)


A = 6*3*3 +9*3x = 3(18+9x) (3)

Draw two rectangles.The first has length 6 and width 9. The second has length 3x and-example-1
User Muhammed Fasil
by
4.4k points