Answer : The mass of
needed are, 44.5 grams.
Explanation :
First we have to calculate the moles of Na.
![\text{Moles of }Na=\frac{\text{Given mass }Na}{\text{Molar mass }Na}=(17.5g)/(23g/mol)=0.761mol](https://img.qammunity.org/2021/formulas/chemistry/middle-school/3qtj1o7jo8itckxyafawg4e0kqqfly2pop.png)
Now we have to calculate the moles of NaCl.
The balanced chemical reaction is:
![2NaCl\rightarrow 2Na+Cl_2](https://img.qammunity.org/2021/formulas/chemistry/middle-school/injnc6h49ojq40hugz121do7ayw0hl9r6m.png)
From the reaction, we conclude that
As, 2 mole of
produces from 2 mole of
![NaCl](https://img.qammunity.org/2021/formulas/chemistry/college/vndawlqlb2f1dgkhd2li1ejb1ucgdqje97.png)
So, 0.761 mole of
produces from 0.761 mole of
![NaCl](https://img.qammunity.org/2021/formulas/chemistry/college/vndawlqlb2f1dgkhd2li1ejb1ucgdqje97.png)
Now we have to calculate the mass of
![NaCl](https://img.qammunity.org/2021/formulas/chemistry/college/vndawlqlb2f1dgkhd2li1ejb1ucgdqje97.png)
![\text{ Mass of }NaCl=\text{ Moles of }NaCl* \text{ Molar mass of }NaCl](https://img.qammunity.org/2021/formulas/chemistry/high-school/hlcwg5j1efub0oykjcih7kbchjwu1vc0sd.png)
Molar mass of
= 58.5 g/mole
![\text{ Mass of }NaCl=(0.761moles)* (58.5g/mole)=44.5g](https://img.qammunity.org/2021/formulas/chemistry/middle-school/lvi9rz0l9o3r0z3adgqgu4gfgmwzhxfq96.png)
Therefore, the mass of
needed are, 44.5 grams.