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What volume will 454.5 grams of Hydrogen gas occupy at 1.050 atm and 25.00 ℃? (Don’t forget Hydrogen gas is diatomic - H2.

User Nisa
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2 Answers

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Answer: The volume occupied by the gas is 5295.1 L

Step-by-step explanation:

To calculate the number of moles, we use the equation:


\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of hydrogen gas = 454.5 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in above equation, we get:


\text{Moles of hydrogen gas}=(454.5g)/(2g/mol)=227.25mol

To calculate the volume, we use the equation given by ideal gas equation:

PV=nRT

where,

P = pressure of the gas = 1.050 at m

V = Volume of gas = ?

n = number of moles of gas = 227.25 moles

R = Gas constant =
0.0821\text{ L atm }mol^(-1)K^(-1)

T = temperature of the gas =
25^oC=[25+273]K=298K[/tex ]</p><p><strong>Putting values in above equation, we get: </strong></p><p>[tex]1.050atm* V=227.25mol* 0.0821\text{ L atm }mol^(-1)K^(-1)* 298K\\\\V=(227.25* 0.0821* 298)/(1.050)=5295.1L

Hence, the volume occupied by the gas is 5295.1 L

User Piotr Leniartek
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5 votes

Answer:

5.24×10^3 L

Step-by-step explanation:

Considering the volume occupied by 454.5g of H2 at 1.050 atm and 25°C.

Likewise, using ideal gas equation.

pV = nRT

What volume will 454.5 grams of Hydrogen gas occupy at 1.050 atm and 25.00 ℃? (Don-example-1
User Erikdstock
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