Question

What volume, in milliliters, of distilled water is needed to make a 9.24 M solution of HCl using 190.0 Grams of HCL? (1 mol HCl = 36.46g HCl)

Answer 1

Answer : The volume of solution needed is, 563.9 mL

Explanation : Given,

Molarity of solution = 9.24 M

Mass of HCl = 190.0 g

Molar mass of
`HCl` = 36.46 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

`\text{Molarity}=\frac{\text{Mass of }HCl* 1000}{\text{Molar mass of }HCl* \text{Volume of solution (in mL)}}`

Now put all the given values in this formula, we get:

`9.24M=\frac{190.0g* 1000}{36.46g/mole* \text{Volume of solution}}`

`\text{Volume of solution}=563.9mL`

Therefore, the volume of solution needed is, 563.9 mL