Answer:
The length of the diagonals are 6mm and 18mm
Explanation:
In this question, we are tasked with calculating the lengths of the diagonals of a rhombus, given the area of the rhombus and how the two diagonals differ from each other.
Mathematically, for a rhombus, we can calculate the area of the rhombus using the formula.
A = 1/2 * d1 * d2
We are also told in the question that one diagonal is there times longer than the other.
So we can say that d1 = 3d2
hence our A becomes;
A = 1/2 * 3d2 * d2
For clarity sake, let’s call d2 d only
Hence
54 = 1/2 * 3d * d
3d^2 = 108
d^2 = 108/3
d^2 = 36
d = square root of 36
d = +6 or -6
we ignore -6 as lengthy cannot be negative
hence d = d2 = 6mm
But d1 = 3d2
d1 = 3 * 6 = 18mm