Question

Find a numerical value of one trigonometric function of x if sin x cot x = 1/3

Answer 1

Answer: see below

Explanation:

sin x cotx = sin x * cos x / sin x = cos x

so cos x = 1/3

Answer 2

`cosx=0.33`

Explanation:

We are given that

`sinxcotx=(1)/(3)`

We have to find the numerical value of one trigonometric function.

We know that

`cotx=(cosx)/(sinx)`

Using the formula then we get

`sinx* (cosx)/(sinx)=(1)/(3)`

`cox=(1)/(3)`

`cosx=0.33`

Hence, the numerical value of one trigonometric function

`cosx=0.33`