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Find the area under the standard normal distribution curve between z=0 amd z=1.38

User Nullable
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1 Answer

1 vote

Answer:


P(0<z<1.38) = P(Z<1.38) -P(Z<0)

And using the normal standard distribution table or excel we got:


P(0<z<1.38) =0.916-0.5= 0.416

The excel code would be:

"=NORM.DIST(1.38,0,1,TRUE) -=NORM.DIST(0,0,1,TRUE)"

Explanation:

For this case we know that our random variable of interest is Z and the distribution is given by:


Z \sim N(\mu =0 , \sigma =1)

This distribution is an special case of the normal distribution.

And we want to find this probability:


P(0<z<1.38)

And we can find this probability with this difference and using the concept of cumulative distribution function for a continuous distribution:


P(0<z<1.38) = P(Z<1.38) -P(Z<0)

And using the normal standard distribution table or excel we got:


P(0<z<1.38) =0.916-0.5= 0.416

The excel code would be:

"=NORM.DIST(1.38,0,1,TRUE) -=NORM.DIST(0,0,1,TRUE)"

User Dmitry Sadakov
by
8.2k points

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