Question

Help me I need the steps

Answer 1

It's a quadratic with a positive x² coefficient, so a CUP, with a minimum

f(x) = 2x² -12 x + 13

= 2(x² - 6x) + 13

= 2(x - 3)² - 2(9) + 13

f(x) = 2(x - 3)² - 5

Since x-3 is always zero or positive the least value is

f(3) = -5

Answer: -5