Answer:
0.72g of gallium
Step-by-step explanation:
Equation of the reduction reaction:
Ga^3+(aq) +3e --------> Ga(s)
If it takes 3F coulumbs of electricity to deposit 70g of gallium (relative atomic mass of gallium)
Then (0.710 × 70×60) coulombs of electricity will deposit (0.710 × 70×60) × 70/3F
But F = 96500C or 1Faraday
Therefore:
(0.710 × 70×60) × 70/3×96500
Mass of gallium deposited= 0.72g of gallium