Answer:
Explanation:
In the question we have given volume of Sphere that is 562.5 π in³ and we have asked to find the radius of given sphere. We know that the volume of sphere ,
![\blue{ \boxed{ \rm{Volume \: of \: Sphere = (4)/(3) \pi r {}^(3) }}}](https://img.qammunity.org/2023/formulas/mathematics/college/ade6p4e5cf1x3w1a8gz21z4d14a7lh40vw.png)
So equating it with given volume for finding the radius of sphere :
![\longmapsto \: (4)/(3) \pi r{}^(3) = 562.5\pi](https://img.qammunity.org/2023/formulas/mathematics/college/ife3c2vtbmbmyvhuh7wnqv7ivrz9q7ir72.png)
Step 1 : Cancelling π as it was present in both side :
![\longmapsto\:(4)/(3) \cancel{\pi }r{}^(3) = 562.5 \cancel{\pi}](https://img.qammunity.org/2023/formulas/mathematics/college/ienzakiitbzmcxtg3q8udhxw6bky5usls0.png)
Step 2 : Transposing 4/3 to right hand side :
![\longmapsto \: r {}^(3) = 562.5 * (3)/(4)](https://img.qammunity.org/2023/formulas/mathematics/college/p027163m696os839m86e3l525oxp1n33vx.png)
Step 3 : Multiplying 562.5 with 3 :
![\longmapsto \:r {}^(3) = (1687.5)/(4)](https://img.qammunity.org/2023/formulas/mathematics/college/dayk34zojqdrim2pzogegmeoijou9rgveo.png)
Step 4 : Dividing 1687.5 by 4 :
![\longmapsto \:r {}^(3) = 421.875](https://img.qammunity.org/2023/formulas/mathematics/college/6bf6g6hcsi2qhs3z2da9ujs8ur0lnozb8f.png)
Step 5 : Finding cube root of 421.875
![\longmapsto \:r = \sqrt[3]{421.875}](https://img.qammunity.org/2023/formulas/mathematics/college/b3z60fgthqwoh1g3dtc6x5s399ppv0aij3.png)
Step 6 : We get :
![\longmapsto \: \red{ \boxed{r = 7.5}}](https://img.qammunity.org/2023/formulas/mathematics/college/gfkjx3na0f6o4lza9mhhxf0qr5opdof97z.png)
- Therefore , radius of sphere is 7.5 inches .
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