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What pressure is exerted by 901.3 g of CH4 in a 0.690 L steel container at 185.7 K

User Emco
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1 Answer

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Ideal gas law: PV = nRT

Write down what you know and what you want to fine:

P = pressure = ?

V = volume in liters = 0.950 L

n = moles = 727.2 g x 1 mol CH4 / 16 g = 45.45 moles

R = gas constant = 0.0821 Latm/Kmol

T = temperature in K = 221.9K

Solve for P:

P = nRT/V = (45.45)(0.0821)(221.9) / 0.950

P = 872 atm (3 sig. figs. based on 0.950 L having 3 s.f.)

User Junuxx
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