Question

Which equations can be used to determine the area of the irregular figure? Check all that apply.

A trapezoid has a base of 4 centimeters, height of 3 centimeters, and top side with a length of 2 centimeters.
A = one-half (3) (2) + 2 (3)
A = one-half (3) (4) + one-half (2) (3)
A = one-half (2) (3) (4)
A = 2 (3) (4)
A = one-half (3) (4) + 2 (3)
A = 3 (4) + 2 (3)

Answer 1

A. A = one-half (3) (2) + 2 (3)

B. A = one-half (3) (4) + one-half (2) (3)

Explanation:

Area of a trapezoid:

½(sum of // sides) × height

½(4 + 2)(3)

½(4)(3) + ½(2)(3)

(2)(3) + ½(2)(3)

Answer 2

A and B

Explanation:

The area of a trapezoid is denoted by:
`A=((b_1+b_2)h)/(2)`, where b_1 and b_2 are the bases and h is the height. Here, b_1 = 2, b_2 = 4, and h = 3. If we plug these values in, we get:

`A=((b_1+b_2)h)/(2)`

`A=((2+4)*3)/(2)=(3*2)/(2) +(3*4)/(2) =(3*2)/(2) +3*2`

Thus, only the first two choices work.

Hope this helps!