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(2y^2 – 3y + 1) = (y - 2)

(2y^2 – 3y + 1) = (y - 2)
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1 vote
(2y^2 – 3y + 1) = (y - 2)

User Nsmeta
by
8.0k points

1 Answer

12 votes

Answer:

see below

Explanation:

Move R side to the L side to get

2y^2 -4y +3 = 0

Use quadratic formula to find y = 1 +- i sqrt (2) / 2

User Rasheedah
by
8.1k points
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