Answer:
Explanation:
Given a right angle triangle,
Where angle Q = 60°
<Q = 60°
And line QR is 2 radical 3.
2 radical 3 implies that 2 root 3
Therefore,
QR = 2√3
Then, we want to find PQ
Since you did not add the diagram and the question did not tell us where the right angle Is,
I will solve the question twice by choosing P as the right angle and also choosing R as the right angle
1. So, when P is right angle
So, check attachment for each of the diagram.
Using Cosine
Cos60 = adjacent / hypotenuse
Cos60 = x / 2√3
Cross multiply
x = 2√3 × Cos60
x = 2√3 × ½
x = √3
x = 1.732
Then, PQ = 2√3
2. When R is the right angle,
Again using cosine
Cos60 = adjacent / hypotenuse
Cos60 = 2√3 / x
Cross multiply
Cos60 × x = 2√3
x = 2√3 / Cos60
x = 2√3 / ½
x = 4√3
x = 6.93
Then, PQ = 4√3