Question

suppose the cooking time for a particular recipe varies inversely with the temperature of the oven. if the recipe takes 60 minutes to cook at a temperature of 350 degrees, how many minutes would it take at 200 degrees

Answer 1

The previous answer did everything correctly but backwards if the temperature goes down the time would go up saying that at 350 it takes 60 minutes to cook then saying at a lower temperature it almost cuts it in half is illogical. Basically what they did was find that to get from 350 to 200 you multiply by .57 but if you look at the question you see the word inversely which means you'd do the opposite to the other thing and logic states this as well so you actually divide 60/.57 and get approximately 105.3 if you round to the tenths. This simply requires you to logically consider that it would go up not down then fix the simple mistake that was made by the falsely verified answer.

Explanation:

Answer 2

It would take 34.29 minutes at 200 degree.

Explanation:

Given that,for a particular recipe the cooking time(t) varies inversely with the temperature(T) of the oven.

t∝T

`\therefore (t_1)/(t_2)=(T_1)/(T_2)`

The recipe takes 60 minutes to cook at a degree temperature of 350 degree,

t₁= 60 minutes, T₁= 350 degree, t₂=?, T₂=200 degree.

`\therefore (t_1)/(t_2)=(T_1)/(T_2)`

`(60)/(t_2)=(350)/(200)`

`\Rightarrow t_2* 350=200* 60`

`\Rightarrow t_2=(200* 60)/(350)`

`\Rightarrow t_2\approx 34.29`

It would take 34.29 minutes at 200 degree.