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In ΔDEF, the measure of ∠F=90°, ED = 65, FE = 56, and DF = 33. What is the value of the sine of ∠D to the nearest hundredth?

2 Answers

6 votes

Answer:0.86

Explanation:

User Robbit
by
5.8k points
4 votes

Answer:

Sine(D)=>0.861

m∠D= 59.42°

Explanation:

Given:

ED = 65

FE = 56

DF = 33

In the right triangle DEF

Sine(D)= Perpendicular / hypotenuse => FE / ED

Sine(D)= 56/ 65 =>0.861

m∠D=
sin^(-1)(56/65)

m∠D= 59.42°

User Krann Sock
by
4.7k points