Komodo dragons are the heaviest lizards on earth. A baby Komodo dragon is 1 3/4 feet long when it hatches. It’s mother is 8 3/4 feet long. An adult male Komodo dragon is 6 times…

Question

asked Nov 25, 2021 187k views

1 Answer

KKM · Answer 1 · 2021-12-01T02:11:30+0000

Answer:

An adult male Komodo dragon is
$10\frac12$ feet.

Therefore the male is
$1\frac34$ feet longer than the mother.

Explanation:

Given that,

A baby dragon is
$1\frac34$ feet long.

It's mother is
$8\frac34$ feet.

An adult male Komodo dragon is 6 times as long as the baby Komodo dragon.

So, an adult male Komodo dragon is =(6×
$1\frac34$ ) feet

$=6* \frac74$ feet

$=\frac61* \frac74$ feet

=
$\frac {21}2$ feet.

$=10\frac12$ feet.

$\therefore 10\frac 12- 8\frac34$

$=(21)/(2)-\frac{35}4$

=(21* 2-35* 1)/(4)

=(42-35)/(4)

$=\frac74$

$=1\frac34$

Therefore the male is
$1\frac34$ feet longer than the mother.